понеделник, 11 юли 2016 г.

one turbine - one compressor (physics)

Diagram 1 - one turbine, one working substance, one compressor, a refrigerant - an option which I will discuss in this post.
 The power of the turbine will be superior to the power of the compressor if the system for redistributing heat returns heat in the evaporator - I will try to prove it by dividing the turbine (1) of two identical turbines and the same two turbines them turn on reverse  to become compressors - chart 2

If the valve 7a is closed and valve 7b open  will  work only  turbine 1b. Compressor 2b expands and compresses refrigerant R as at enlargement takes heat from the working substance A  after the turbine in a heat exchanger 4b to a temperature equal  or less to  the boiling point of the working substance A so that it liquefies. The heat that we take from the working substance A is transmitted to the liquid working substance in a heat exchanger 5 where  compressor 2b compresses the refrigerant R. As I said above compressor 2b  is a reverse turbine 1b so that by conservation of energy should: If power of turbine apply it to the compressor working substance A before the turbine and then the compressor must have the same parameters - temperature, volume and pressure .
Waut b = Win b
The same forces - no change in the parameters of the working substance - no effective unit. There is no way to apply a small force to the compressor so to us remain useful energy because we can not take away heat and give it to another body so that the unit can not hold amounts of heat.
We begin to open valve 7a.  Turbine 1a starts. The same one reverse turbine is a compressor 2a, which expands and compresses refrigerant R so that at enlargement in heat exchanger 4a removes heat from the working substance A after turbine 1a to liquefaction. The heat which is removed from the working substance in a heat exchanger 4a return it to the evaporator 3. Pump refers working substance  A at a temperature equal  or lower than the boiling point of the heat exchanger 4a  to the heat exchanger 5.
To compare the forces of tubes 1a and reverse turbine  - compressor 2a : Turbine 1a works to a temperature difference T2 / Tbp and produces power Wout. By the laws of thermodynamics - compressor 2a overcomes temperature difference T2 / Tbp so that it would need  force Wina equal to the force produced by the turbine  Wouta
Wout a = Win a
How does the inclusion of a turbine 1a and compressor  2a of the balance of power Wout b and Winb?? Compressor 2b must give warmth that refrigerant R is accepted at expansion in heat exchanger 4b of working substance A on a large amount of working substance in a heat exchanger 5, because working substance after heat exchanger 4a is collected by the working substance of the heat exchanger 4b. This violates equality  Woutb = Winb
Because the compressor 2b to overcome a small temperature difference therefore:
Win b <Wout b
 Net power to the entire unit is:
W =  Wouta + Woutb - Wina - Winb
Considering that  Wout a = Win a
W = Wout b – Win b
So  such a unit will have a beneficial force.
As unite heat exchangers 4a and 4b,  unite turbine 1a and 1b  and compressors 2a and 2b proceed to an efficient engine where Wout > Win - figure 1a

In this line of thinking exchanger 5 may be unnecessary - chart 3 (it is derived from the chart 1 depending on the setting of valves 7)

All waste heat return it to the evaporator 3. This will lead to higher temperatures T2 and a small amount of circulation of the working substance

четвъртък, 7 юли 2016 г.

n number of turbines engine on endothermic chemical processes

If the capacity of the solution is too little to cool the working substance to a temperature below its boiling point, will have to reduce the amount of waste heat. Let that be a n of the number of working substances  unit as I drew on diagram 1.

For me it is not known what are the possibilities of endothermic solutions to cool, but at the expense of this issue of reducing waste heat I am debate  in physical methods for creating cold part. So in short:
Several working substances - a, b ... n each with a lower boiling point. Solvent α heated working substance a above its boiling point; due to the heat exchange between a and b a  liquefies and b boiling ... and so to working substance n .
Solvent α heat exchange with each of the evaporators on working substances. The latter working substance n should have a boiling point lower than the boiling point of the solvent  α and higher than the boiling point of the solution αβ . So working substance n liquefies solvent  α , and the solution αβ  closes the cycle of working substance n.

Probably every one variant of the physical method I've drawn may be converted to chemical - with a one working substance, with n of number of working substances and two working substances with a common cold part, so small capacity (possibly) of cooling on solution hope it is not a problem.


For а less waste heat would be appropriate to have another heat exchange between the solvent α and the last working substance n as in chart 2

вторник, 5 юли 2016 г.

one turbine engine on solution

It is good one to give a break from work. "Vacationing makes champions" - are increasingly convinced of the rightness of this maxim lol
So did I - I gave myself  three weeks vacation on "an internal cooling engine" and  after returned  saw that the engine using the endothermic solution for obtaining low temperatures of the cold part is not necessarily to be on two working substances and two turbines. The possibility - second working substance with low boiling point as doing work to create the liquid solvent is not bad, but the possibility - solution to create liquid solvent is even better because we eliminate one turbine and unit becomes small and compact.

Here's patent application which  handed today  (Chart 1)
 αβ  - endothermic solution
 α    - solvent
 β   -   solute

I would like to ask if anyone had guessed this opportunity as diagram1, аnd he has filed an application before me (not  too hard to guess, and I think that at least 4 teams of very good specialists in various places in the world  working on internal cooling engine) - Please write to me at:

I will withdraw  this application  to save my costs on this application

Many thanks

Svetozar the Cold

сряда, 18 май 2016 г.

Wanted solvent and solute

Reflections on the motive power on heat of the environment and on machines fitted to develop that power

I imagined that the issue goes beyond physics and moves in the field of chemistry, and will have to leave ... but it is not easy to me stop thinking about it. These are ten years till now - think themselves come, whether I want or do not want. So since I announced that I stop, I saw development for the physical framework of the process of making the cold part of the unit with endothermic chemical processes. Even a "devil" whispered to me: "Do not be silly! Patented it!" The "devil"  managed to tempt me ,and I handed application with the patent office. Here's how things went with endothermic processes:
Previous post ended like this:

I thought, Wait a minute! You should be warm and working substance in the environment. I was thinking about chemical processes and have neglected the physical basis for them and engine. But physics should outline the basics to open bigger opportunities for chemistry.  So things came to diagram 4

Then they seized me thinks - Will I get cold in the cold part after heat up the working substance in the environment, and then again with the exothermic reaction between α and β ? Instead of turning to energy equations I saw technical solution: We will use the mixer – diagram 5

Control valves 13 and 14, and so the temperature of the working substance we can change  from the temperature of the heat exchanger 1 (when the valve 14 is closed) to ambient temperature (when the valve 13 is closed).
Then I saw the flaw in this chart -  waste a cold. Unit will become more efficient  if we use cold working substance and compound out of the cold part to cool the α and β  before entering the heat exchanger 1.  So the device evolved as chart 6

Evolution underwent and unit using an endothermic solution for low temperatures in the cold part diagram 7

For example - solvent α is ammonia (240K;  boiling point). At a temperature of 290K (17C) ammonia gases have a pressure of 8 MPa. Solute αβ to be a mystical salts  AxBy. Hypothetically - AxBy was dissolved in ammonia by this chemical process is endothermic.
Working substance γ let's fluoromethyl CH3F (R-41; 195K bp).
In the heat exchanger 1 of the drawing 7 ammonia boils and the solution was separated into ammonia and AxBy. Ammonia gases perform work in the turbine 5, where they enter the heat exchanger 2. In heat exchanger 2 ammonia liquefies due to heat exchange with the liquid working substance CH3F. A pump (7) takes the liquid ammonia in the heat exchanger 3.
Salts AxBy separated from the solution pump 8 (probably screw) them ending up at 4 heat exchanger to cool them before you take them in a heat exchanger 3 diagram 7.
 Working substance CH3F is pre-cooled and liquefied to a temperature between its boiling point and its freezing point. In heat exchanger 2, it is heated to a temperature of 240K. The pressure is increased and it is boiling. Gases CH3F perform work in the turbine 6. From there enter the heat exchanger 3 where liquefy due to low temperature created by the dissolution of salts AxBy in the solvent  ammonia. Pump 7 takes liquified working substance CH3F first in heat exchanger 4 to cool the solute AxBy and then in heat exchanger 2 to receive heat from the gases ammonia and so the cycle of working substance is repeated.
Ammonia boiling in the heat exchanger 1, perform work in the turbine 5, salts are dissolved in ammonia in the heat exchanger 3, solution heat exchange first with AxBy in a heat exchanger 4, then (possibly) with ammonia and fluoromethyl in a heat exchanger 2 and out of the heat insulating part where is  heat exchanger 1 to heat from the surrounding environment and the process to begin again. In this renewable process would receive mechanical energy from both turbines 5 and 6 at the expense of the heat of the environment:

W = W1 + W2 = Q in