Let's go back to the philosophy of external combustion engine

Let's go back to the philosophy of external combustion engine - is required temperature difference between the hot and cold part to be able to convert heat into mechanical work.  Now we heat the warm part to have a temperature difference. I suggest that the temperature difference to be a result of work done - temperature difference between the hot and cold part we can create it as a cooling cold part. And to get efficient engine has the power we need to apply to create the necessary temperature difference at any time should be less than the force that generates the working substance.
Lets to think - how much is the heat which we can turn into mechanical work of a working substance with a given temperature? To be able to work  working substance must have a temperature -high from its boiling point. All the heat of a working substance which can be converted into mechanical work it is equal to the difference between  the temperature to which it heats the heat source up to its boiling point. Theoretically and practically we can make all this heat into mechanical work always remained  waste heat.
Let's perform work on the working substance as it cooled in the cold part to have a temperature difference and the engine running. To be an effective engine running on this principle should amount to heat is less than the amount of heat which has become into mechanical energy. This will achieve it by carrying out the process of converting heat into mechanical energy into heat - isolated environment - on the work process working substance cools. So like I can become a a large part of  the heat into mechanical force balance between the useful power and strength that must apply in order to maintain the temperature difference will be in favor of the beneficial forces. I think there is a way beneficial forces are more powerful than  the opposite and so we have an effective engine of which the temperature difference between hot and cold part is held as a result of work done.
We need to create conditions for the majority of the amount of heat on the working substance to turn into mechanical energy so that the waste heat to be a small part of the total heat quantity.
In my previous posts I have given some suggestions (It is better to begin consideration of the method with two working substances). I have a few more ideas that will present soon.
One primary method is to use more than one working substance. Each working substance can convert think ½ of the amount of heat into mechanical work. So the power we need to use for running the unit at any time will be measuring less than power produced by the working substances in their work.
Another method is to split the load and repeatedly perform work as the opportunity to make heat exchange between liquid and gaseous working substance in the course of his work. So I want to achieve a small amount of waste heat before closing the cycle of working substance. Less waste  heat = good balance between useful and opposite force.
To draw attention once again to something important - Every start we need to have set a low temperature of the cold part. This will use external power.

To load repeatedly and exchanging heat to be effective unit.

If we resolve on working substance to expand (evaporates) without conducting enough work then to close the cycle we will need a large force to apply on it. At the same time there is no way to spread the load of single evaporator- turbine to decline in the course of work - to make the most of the opportunities of working substance. I therefore suggest that the same amount of working substance to perform multiple work as it passes from one evaporator to another with increasingly lower temperatures. In this way I can load the given amount of substance to work up and to take to cool and gaseous working substance due to heat exchange. A "cooler" loaded with a substance with a low boiling point(R41)  at the end. Its task is to cool the gas to liquefaction - Chart 4.

 When proceeding to closing the cycle the gaseous working substance will have a temperature close to the boiling point and the power necessary for compressor 5 will be smaller than the power received from the plurality of converters of heat into mechanical energy 7. Such a unit will be effective.

I guess we can close the cycle of the unit with a "clean power"

Let's apply a "clean power" on the last working substance (with the lowest boiling point) - gas is liquefied under pressure of compressor and not because of the low temperature generated by the compressor on cooler ( in my patent I use the old - System of  Redistribution on Heat , instead cooler).

Chart 1c -  two working substances and compressor.

My opinion is that such a unit would not be effective - Two forces useful – turbine, against one opposite - the compressor which is equal to two useful. The ratio useful to opposing forces - 2 to 2? (But just in case I have stated in the patent claims IoI )

Chart 3c - three working substances and compressor.

My opinion is that this unit will be effective - three useful energy (turbines) against the compressor - a ratio of beneficial to opposing forces - 3 to 2?

Accept objections (not only for versions with "clean power").

I patented and other effective (by me) variants of external combustion - internal cooling engine, which put them in my blog next week. There are interesting "thermodynamic - mechanical puzzles." I think it is worth a look dear readers.

Method and device with more than one working substance

        External combustion engine with closed cycle of working substance. The cycle closes as a result of applied work on the working substance, unlike the current engines, cycle on which closes as a result of heat exchange.

Recently I added another method for external combustion engine and internal cooling - using more than one working substance. I think that gets efficient engine - the work that needs to use to close the cycle is less than the resulting production work.

Look at the following chart, which represents the external combustion engine with two working substances – diagram 1.

 Both work in a closed cycle,  and two-cycle heat exchange with each other. As a result of the heat exchange cycle of the first (water) is closed. The second (diethyl ether) I will add force to close its cycle - compressor 5 will cool the gas to its liquefaction . The first (water) heat exchange with the heat source. Second (diethyl ether) is working in heat isolated environment -17  is thermal insulation. Gases ether after turbine 7  entering the "fridge" 4. There due to the operation of the compressor 5 and an expansion valve 18  the ammonia which is charged "refrigerator" was evaporated, and to dissipate the heat of the gases ether to liquefy them.

For such an engine there are two useful power - turbines 6 and 7 and one an opposite - of the compressor 5. If we ignore the energy needed to run the pumps 9 and 10  my opinion is that this engine will work - two useful forces against one opposing force to them. Should remain our mechanical force in "profit".

If you agree with those of my assumptions - I suggest you go down to the lower temperatures and other working substances as in diagram 2.

Things on chart 2 are the same as chart 1 - two useful energy from the turbines to the opposite one of them - the compressor on "the refrigerator".

Three working substances - diagram 3

ammonia -  240K B.P.

R 41         -   195K B.P.

R 14       -     145K B.P.

On refrigerant  - Nitrogen -    77K   B.P. 

Two cycles (ammonia; R 41) closed free - as a result of heat exchange (as is the traditional external combustion engine). A cycle on R14 closed as a result of work done on the working substance ( by compressor 5). The ratio of beneficial to the opposing forces  is 3 to 1? - three turbines to the compressor.

If comparing the temperature difference start - end to the temperature difference that must be overcome compressor on "refrigerator":

290-167 = 123 degrees

167-142 = 25 degrees

123/25 - the approximate ratio of useful energy to opposing force - 5 to 1?

Most true than I think it should be given the quantities of heat – Ideally each working substance in its working cycle  may become 50% of the amount of heat into mechanical force. So after the first remaining 1/2, after second 1/4 and  remains after the third 1/8 of the original amount of heat. So the power we need to apply to the compressor on "cooler" to the useful will relate 8 to 1? in favor of the beneficial forces, (ignoring the operation of the pumps).

To draw attention - working substances in the insulated part of a temperature below the boiling point - pre-cool them to run the unit.