External combustion engine with closed
cycle of working substance. The cycle closes as a result of applied work on the
working substance, unlike the current engines, cycle on
which closes as a result of heat exchange.
Look
at the following chart, which represents the external combustion engine with
two working substances – diagram 1.
Both work in a closed cycle, and two-cycle heat exchange with each other.
As a result of the heat exchange cycle of the first (water) is closed. The
second (diethyl ether) I will add force to close its cycle - compressor 5 will
cool the gas to its liquefaction . The first (water) heat exchange with the
heat source. Second (diethyl ether) is working in heat isolated environment -17
is thermal insulation. Gases ether after
turbine 7 entering the
"fridge" 4. There due to the operation of the compressor 5 and an
expansion valve 18 the ammonia which is
charged "refrigerator" was evaporated, and to dissipate the heat of
the gases ether to liquefy them.
For
such an engine there are two useful power - turbines 6 and 7 and one an
opposite - of the compressor 5. If we ignore the energy needed to run the pumps
9 and 10 my opinion is that this engine
will work - two useful forces against one opposing force to them. Should remain
our mechanical force in "profit".
If
you agree with those of my assumptions - I suggest you go down to the lower
temperatures and other working substances as in diagram 2.
Things
on chart 2 are the same as chart 1 - two useful energy from the turbines to the
opposite one of them - the compressor on "the refrigerator".
Three
working substances - diagram 3
ammonia
- 240K B.P.
R
41 - 195K B.P.
R
14 - 145K B.P.
On refrigerant - Nitrogen
- 77K B.P.
Two
cycles (ammonia; R 41) closed free - as a result of heat exchange (as is the
traditional external combustion engine). A cycle on R14 closed as a result of
work done on the working substance ( by compressor 5). The ratio of beneficial
to the opposing forces is 3 to 1? - three
turbines to the compressor.
If comparing the temperature difference start - end
to the temperature difference that must be overcome compressor on
"refrigerator":
290-167
= 123 degrees
167-142
= 25 degrees
123/25
- the approximate ratio of useful energy to opposing force - 5 to 1?
Most
true than I think it should be given the quantities of heat – Ideally each
working substance in its working cycle may become 50% of the amount of heat into
mechanical force. So after the first remaining 1/2, after second 1/4 and remains after the third 1/8 of the original
amount of heat. So the power we need to apply to the compressor on
"cooler" to the useful will relate 8 to 1? in favor of the beneficial
forces, (ignoring the operation of the pumps).
To
draw attention - working substances in the insulated part of a temperature
below the boiling point - pre-cool them to run the unit.
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